Strongly isospectral hyperbolic 3-manifolds with nonisomorphic rational cohomology rings
Abstract
This paper shows that one cannot "hear" the rational cohomology ring of a hyperbolic 3-manifold. More precisely, while it is well-known that strongly isospectral manifolds have the same cohomology as vector spaces, we give an example of compact hyperbolic 3-manifolds that are strongly isospectral but have nonisomorphic rational cohomology rings. Along the way we implement a computer program which finds the nullity of the cup product map $H^1(M;\mathbb{Q})\wedge H^1(M;\mathbb{Q})\rightarrow H^2(M;\mathbb{Q})$ for any aspherical space in terms of the presentation of the fundamental group.
- Publication:
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arXiv e-prints
- Pub Date:
- November 2021
- DOI:
- 10.48550/arXiv.2111.11454
- arXiv:
- arXiv:2111.11454
- Bibcode:
- 2021arXiv211111454T
- Keywords:
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- Mathematics - Geometric Topology;
- Mathematics - Differential Geometry
- E-Print:
- 11 pages