We argue that an organic superconductor (TMTSF)2PF6 under pressure P = 6 kbar is a triplet superconductor1,2 with a spin part of the triplet order parameter being d(k) = (dx (k) ≠ 0, dy (k) = 0, dz (k) =0). We obtain these results by means of an analysis of the anisotropic experimental critical fields Hc2 (see I. J. Lee et al., Phys. Rev. Lett. 78, 3555 (1997)). By using symmetry arguments, we also discuss the most probably orbital part of the triplet order parameter in (TMTSF)2PF6. Our analysis is in accordance with the very recent Knight shift data obtained on (TMTSF)2PF6.